The Continue Command is Interpreted by the forloop as
Loops/Continue
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Show the following output using one loop.
1, 2, 3, 4, 5 6, 7, 8, 9, 10
Try to achieve the result by forcing the next iteration within the loop upon a specific condition, if your language allows it.
- Related tasks
- Loop over multiple arrays simultaneously
- Loops/Break
- Loops/Continue
- Loops/Do-while
- Loops/Downward for
- Loops/For
- Loops/For with a specified step
- Loops/Foreach
- Loops/Increment loop index within loop body
- Loops/Infinite
- Loops/N plus one half
- Loops/Nested
- Loops/While
- Loops/with multiple ranges
- Loops/Wrong ranges
11l [edit]
L(i) 1..10 I i % 5 == 0 print(i) L.continue print(i, end' ', ') 1, 2, 3, 4, 5 6, 7, 8, 9, 10
360 Assembly [edit]
* Loops/Continue 12/08/2015 LOOPCONT CSECT USING LOOPCONT,R12 LR R12,R15 BEGIN LA R8,0 SR R5,R5 LA R6,1 LA R7,10 LOOPI BXH R5,R6,ELOOPI for i=1 to 10 LA R3,MVC(R8) XDECO R5,XDEC MVC 0(4,R3),XDEC+8 LA R8,4(R8) LR R10,R5 LA R1,5 SRDA R10,32 DR R10,R1 LTR R10,R10 BNZ COMMA XPRNT MVC,80 LA R8,0 B NEXTI COMMA LA R3,MVC(R8) MVC 0(2,R3),=C', ' LA R8,2(R8) NEXTI B LOOPI next i ELOOPI XR R15,R15 BR R14 MVC DC CL80' ' XDEC DS CL16 YREGS END LOOPCONT 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Ada [edit]
Ada doesn't have a continue statement, so we have to use a goto statement. The previous submitter said continue is not needed. In this example it is indeed not needed, but that is not always the case. An example is a loop where a number of interdependent conditions are checked before executing the main body of the loop. Without a continue statement (or goto), one ends up with nested statements with the main body to the far right of the page.
B.N. You should always try to avoid using a goto, but if you really must, it's there in Ada.
P.S. it is often simplest to place the label on top of the loop, as in real life the need occurs when reading input, so there is no range condition in the loop and we can forgo the null statement.
with Ada.Text_IO ; use Ada.Text_IO ; procedure Loop_Continue is begin for I in 1. . 10 loop Put ( Integer ' Image ( I )); if I = 5 or I = 10 then New_Line ; goto Continue ; end if ; Put ( "," ); <<Continue>> --Ada 2012 no longer requires a statement after the label end loop ; end Loop _Continue ; N. This is a more true-to-Ada strategy for 'continue' comprising of an outer iteration loop and an inner labeled single-pass loop. This is a safer strategy than using goto which could be problematic when dealing with complex nested loops.
with Ada.Text_IO ; use Ada.Text_IO ; procedure Loop_Continue is begin Print_All : for I in 1 .. 10 loop Print_Element : loop Put ( Integer ' Image ( I )); if I = 5 or I = 10 then New_Line ; exit Print_Element ; end if ; Put ( "," ); exit Print_Element ; end loop Print_Element ; end loop Print_All ; end Loop _Continue ; Agena [edit]
Agena doesn't have a continue statement, conditional statements can be used instead.
for i to 10 do write( i ); if i % 5 = 0 then write( "\n" ) else write( ", " ) fi od Aikido [edit]
foreach i 1..10 { print (i) if ((i % 5) == 0) { println() continue } print (", ") } ALGOL 60 [edit]
begin integer i; for i:=1 step 1 until 10 do begin outinteger(i); if i=(i div 5)*5 then outimage else outstring(", ") end end +1 , +2 , +3 , +4 , +5 +6 , +7 , +8 , +9 , +10
ALGOL 68 [edit]
ALGOL 68 has no continue reserved word, nor does it need one. The continue reserved word is only syntactic sugar for operations that can be achieved without it as in the following example:
FOR i FROM 1 TO 10 DO print ((i, IF i MOD 5 = 0 THEN new line ELSE "," FI )) OD +1, +2, +3, +4, +5 +6, +7, +8, +9, +10
ALGOL W [edit]
Algol W doesn't have a continue statement - conditional statements can be used instead.
begin i_w := 1; s_w := 0; % set output format % for i := 1 until 10 do begin writeon( i ); if i rem 5 = 0 then write() else writeon( ", " ) end for_i end. AppleScript [edit]
set table to { return } repeat with i from 1 to 10 if i < 5 or ( i ≥ 6 and i < 10 ) then set end of table to i & ", " else if i = 5 or i = 10 then set end of table to i & return end if end repeat return table as string " 1, 2, 3, 4, 5 6, 7, 8, 9, 10 "
Arturo [edit]
loop 1..10 'i [ prints i if 0 = i%5 [ print "" continue ] prints ", " ] 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Asymptote [edit]
Asymptote's control structures are similar to those in C/C++
for ( int i = 1 ; i <= 10 ; ++ i ) { write ( i , suffix = none ); if ( i % 5 == 0 ) { write ( "" ); continue ; } else { write ( ", " , suffix = none ); } } AutoHotkey [edit]
Loop , 10 { Delimiter := ( A_Index = 5 ) || ( A_Index = 10 ) ? " `n " : ", " Index .= A_Index . Delimiter } MsgBox %Index% AWK [edit]
BEGIN { for ( i = 1 ; i <= 10 ; i ++ ) { printf ( "%d" , i ) if ( i % 5 == 0 ) { print continue } printf ( ", " ) } } BASIC [edit]
Applesoft BASIC [edit]
10 FOR I = 1 TO 10 20 PRINT I; 30 IF I - INT (I / 5) * 5 = 0 THEN PRINT : GOTO 50"CONTINUE 40 PRINT ", "; 50 NEXT BASIC256 [edit]
for i = 1 to 10 print string(i); if i mod 5 = 0 then print continue for end if print ", "; next print end BBC BASIC [edit]
BBC BASIC doesn't have a 'continue' statement so the remainder of the loop must be made conditional.
FOR i% = 1 TO 10 PRINT ; i% ; IF i% MOD 5 = 0 PRINT ELSE PRINT ", " ; NEXT Commodore BASIC [edit]
Commodore BASIC also doesn't have a 'continue' statement. In this example, a GOTO statement is used to simulate 'CONTINUE'. However, Commodore BASIC doesn't have a modulo (remainder) operator, so value of I/5 is check against INT(I/5). If they are the same, the remainder is zero.
10 FOR I = 1 to 10 20 PRINT I ; 30 IF INT ( I / 5 ) = I / 5 THEN PRINT : GOTO 50 40 PRINT ", " ; 50 NEXT FreeBASIC [edit]
' FB 1.05.0 Win64 For i As Integer = 1 To 10 Print Str ( i ); If i Mod 5 = 0 Then Print Continue For End If Print ", " ; Next Print Sleep 1, 2, 3, 4, 5 6, 7, 8, 9, 10
IS-BASIC [edit]
100 FOR I=1 TO 10 110 PRINT STR$(I); 120 IF MOD(I,5)=0 THEN 130 PRINT 140 ELSE 150 PRINT ", "; 160 END IF 170 NEXT Liberty BASIC [edit]
for i =1 to 10 if i mod 5 <>0 then print i; ", "; else print i next i end PureBasic [edit]
OpenConsole () For i . i = 1 To 10 Print ( Str ( i )) If i % 5 = 0 PrintN ( "" ) Continue EndIf Print ( "," ) Next Repeat: Until Inkey () <> "" QB64 [edit]
Dim i As Integer For i = 1 To 10 Print LTrim$(Str$(i)); If i Mod 5 = 0 Then Print _Continue End If Print ", "; Next Run BASIC [edit]
for i = 1 to 10 if i mod 5 <> 0 then print i;", "; else print i next i Sinclair ZX81 BASIC [edit]
This probably isn't the most idiomatic way to produce the specified output—but it does illustrate ZX81 BASIC's equivalent of if <condition> continue, which is IF <condition> THEN NEXT <loop-control variable>.
10 FOR I=1 TO 10 20 PRINT I; 30 IF I/5=INT (I/5) THEN PRINT 40 IF I/5=INT (I/5) THEN NEXT I 50 PRINT ", "; 60 NEXT I TI-89 BASIC [edit]
count() Prgm ""→s For i,1,10 s&string(i)→s If mod(i,5)=0 Then Disp s ""→s Cycle EndIf s&", "→s EndFor EndPrgm Ti-89 lacks support for multi-argument display command or controlling the print position so that one can print several data on the same line. The display command (Disp) only accepts one argument and prints it on a single line (causing a line a feed at the end, so that the next Disp command will print in the next line). The solution is appending data to a string (s), using the concatenator operator (&), by converting numbers to strings, and then printing the string at the end of the line.
True BASIC [edit]
FOR i = 1 TO 10 PRINT STR$ ( i ); IF REMAINDER ( i , 5 ) = 0 THEN PRINT ELSE ! No existe el comando CONTINUE PRINT ", " ; END IF NEXT i PRINT END VB-DOS, PDS [edit]
OPTION EXPLICIT DIM i AS INTEGER CLS FOR i = 1 TO 10 PRINT STR$ ( i ); IF ( i MOD 5 ) THEN PRINT "," ; ELSE PRINT NEXT i END Visual Basic .NET [edit]
For i = 1 To 10 Console . Write ( i ) If i Mod 5 = 0 Then Console . WriteLine () Else Console . Write ( ", " ) End If Next bc [edit]
Requires a bc with the print and continue statements. POSIX bc has not these statements.
for (i = 1 ; i <= 10 ; i++ ) { print i if (i % 5 ) { print ", " continue } print "\n" } quit Befunge [edit]
Befunge outputs numbers with a space after them, so the formatting is slightly off in this version.
1 > : 56 + \ ` # v _@ + v % 5 :.: < 1 > # v _ 55 + , v ^ < > " ," ,, v ^ < This version outputs a 'backspace' ASCII character to try to correct the format, but it may or may not work depending on if the character is accounted for by the output
1 > : 56 + \ ` # v _@ + v 5 :, 8 .: < 1 > % # v _ 55 + , v ^ < > " ," , v ^ , < Bracmat [edit]
Bracmat has no continue statement.
( 0:?i & whl ' ( 1+!i:~>10:?i & put $ ( str $ ( !i (mod$(!i.5):0&\n|", ") ) ) ) ); C [edit]
for ( int i = 1 ; i <= 10 ; i ++ ){ printf ( "%d" , i ); if ( i % 5 == 0 ){ printf ( " \n " ); continue ; } printf ( ", " ); } C# [edit]
using System ; class Program { static void Main ( string [] args ) { for ( int i = 1 ; i <= 10 ; i ++) { Console . Write ( i ); if ( i % 5 == 0 ) { Console . WriteLine (); continue ; } Console . Write ( ", " ); } } } C++ [edit]
for ( int i = 1 ; i <= 10 ; i ++ ){ cout << i ; if ( i % 5 == 0 ){ cout << endl ; continue ; } cout << ", " ; } Chapel [edit]
for i in 1 .. 10 { write ( i ); if i % 5 == 0 then { writeln (); continue ; } write ( ", " ); } Clipper [edit]
LOOP keyword is used here instead of continue.
Works as is with Harbour 3.0.0 (Rev. 16951)
FOR i := 1 TO 10 ?? i IF i % 5 == 0 ? LOOP ENDIF ?? ", " NEXT Clojure [edit]
Clojure doesn't have a continue keyword. It has a recur keyword, although I prefer to work with ranges in this case.
( doseq [ n ( range 1 11 )] ( print n ) ( if ( zero? ( rem n 5 )) ( println ) ( print ", " ))) To address the task, however, here's an example loop/recur:
( loop [ xs ( range 1 11 )] ( when-let [ x ( first xs )] ( print x ) ( if ( zero? ( rem x 5 )) ( println ) ( print ", " )) ( recur ( rest xs )))) COBOL [edit]
IDENTIFICATION DIVISION . PROGRAM-ID . loop-continue . DATA DIVISION . WORKING-STORAGE SECTION . 01 i PIC 99 . PROCEDURE DIVISION . PERFORM VARYING i FROM 1 BY 1 UNTIL 10 < i DISPLAY i WITH NO ADVANCING IF FUNCTION MOD ( i , 5 ) = 0 DISPLAY SPACE EXIT PERFORM CYCLE END-IF DISPLAY ", " WITH NO ADVANCING END-PERFORM GOBACK . Note: COBOL does have a CONTINUE verb, but this is a no-operation statement used in IF and EVALUATE statements.
ColdFusion [edit]
Remove the leading space from the line break tag.
<cfscript> for ( i = 1 ; i <= 10 ; i ++ ) { writeOutput ( i ); if ( 0 == i % 5 ) { writeOutput ( "< br />" ); continue ; } writeOutput ( "," ); } </cfscript> Common Lisp [edit]
Common Lisp doesn't have a continue keyword, but the do iteration construct does use an implicit tagbody, so it's easy to go to any label. Four solutions follow. The first pushes the conditional (whether to print a comma and a space or a newline) into the format string. The second uses the implicit tagbody and go. The third is a do loop with conditionals outside of the output functions.
( do (( i 1 ( 1+ i ))) (( > i 10 )) ( format t "~a~:[, ~;~%~]" i ( zerop ( mod i 5 )))) ( do (( i 1 ( 1+ i ))) (( > i 10 )) ( write i ) ( when ( zerop ( mod i 5 )) ( terpri ) ( go end )) ( write-string ", " ) end ) ( do (( i 1 ( 1+ i ))) (( > i 10 )) ( write i ) ( if ( zerop ( mod i 5 )) ( terpri ) ( write-string ", " ))) These use the loop iteration form, which does not contain an implicit tagbody (though one could be explicitly included). The first uses an explicit condition to omit the rest of the loop; the second uses block/return-from to obtain the effect of skipping the rest of the code in the block which makes up the entire loop body.
( loop for i from 1 to 10 do ( write i ) if ( zerop ( mod i 5 )) do ( terpri ) else do ( write-string ", " )) ( loop for i from 1 to 10 do ( block continue ( write i ) ( when ( zerop ( mod i 5 )) ( terpri ) ( return-from continue )) ( write-string ", " ))) D [edit]
import std . stdio ; void main () { foreach ( i ; 1 .. 11 ) { write ( i ); if ( i % 5 == 0 ) { writeln (); continue ; } write ( ", " ); } } 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Shorter version [edit]
import std . stdio ; void main () { foreach ( i ; 1..11 ) i % 5 ? writef ( "%s, " , i ) : writeln ( i ); } dc [edit]
The four commands # n J M are special to OpenBSD dc. The # command starts a comment. The n command prints a number without a newline.
1 si # i = 1 [2Q]sA # A = code to break loop [[, ]P 1J]sB # B = code to print comma, continue loop [ li n # print i li 5 % 0 !=B # call B if i % 5 [ ]P # print newline M # mark from calling B li 1 + si # i += 1 li 10!<C # continue loop if 10 >= i ]sC li 10!<C # enter loop if 10 >= i This program uses J and M to force the next iteration of a loop. The nJ command breaks n levels of brackets (like nQ does so), but then skips to the next M command. One can place M at the end of the iteration.
Delphi [edit]
program DoLoop ( output ) ; var i : integer ; begin for i := 1 to 10 do begin write ( i ) ; if i mod 5 = 0 then begin writeln ; continue ; end ; write ( ', ' ) ; end ; end . 1, 2, 3, 4, 5 6, 7, 8, 9, 10
DWScript [edit]
var i : Integer ; for i := 1 to 10 do begin Print ( i ) ; if i mod 5 = 0 then begin PrintLn ( '' ) ; continue ; end ; Print ( ', ' ) ; end ; Dyalect [edit]
for i in 1..10 { print(i, terminator: "") if i % 5 == 0 { print() continue } print(", ", terminator: "") } 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Ela [edit]
Direct Approach [edit]
open monad io loop n = if n > 10 then do return () else do putStr (show n) putStr f loop (n + 1) where f | n % 5 == 0 = "\r\n" | else = ", " _ = loop 1 ::: IO Using list [edit]
open monad io loop [] = return () loop (x::xs) = do putStr (show x) putStr f loop xs where f | x % 5 == 0 = "\r\n" | else = ", " _ = loop [1..10] ::: IO This version is more generic and can work for any given range of values.
Elixir [edit]
defmodule Loops do def continue do Enum . each ( 1 .. 10 , fn i -> IO . write i IO . write if rem ( i , 5 ) == 0 , do : " \n " , else : ", " end ) end end Loops . continue 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Erlang [edit]
%% Implemented by Arjun Sunel - module ( continue ). - export ([ main / 0 , for_loop / 1 ]). main () -> for_loop ( 1 ). for_loop ( N ) when N /= 5 , N < 10 -> io : format ( " ~p , " ,[ N ] ), for_loop ( N + 1 ); for_loop ( N ) when N >= 10 -> if N =:= 10 -> io : format ( " ~p \n " ,[ N ] ) end ; for_loop ( N ) -> if N =:= 5 -> io : format ( " ~p \n " ,[ N ] ), for_loop ( N + 1 ) end . 1, 2, 3, 4, 5 6, 7, 8, 9, 10 ok
ERRE [edit]
FOR I=1 TO 10 DO PRINT(I;CHR$(29);) ! printing a numeric value leaves a blank after it ! chr$(29) delete it..... IF I MOD 5=0 THEN PRINT CONTINUE FOR END IF PRINT(",";) END FOR PRINT Euphoria [edit]
include std\console.e --only for any_key to make running command window easier on windows for i = 1 to 10 do if remainder(i,5) = 0 then printf(1, "%d\n", i) else printf(1,"%d, ", i) continue end if end for any_key() Version without newline after 10 below.
include std\console.e --only for any_key to make running command window easier on windows for i = 1 to 10 do if remainder(i,5) = 0 then switch i do case 10 then printf(1,"%d ",i) break --new to euphoria 4.0.0+ case else printf(1,"%d\n", i) end switch else printf(1,"%d, ", i) continue --new to euphoria 4.0.0+ end if end for any_key() F# [edit]
continue is a reserved word, but it has no function. In any case, it is not needed to complete this task.
[edit]
for i in 1 .. 10 do printf "%d" i if i % 5 = 0 then printf " \n " else printf ", " Using Comma quibbling#The Function [edit]
let fN g = quibble ( Seq . initInfinite ( fun n -> if ( n + 1 )% 5 = 0 || ( n + 1 )= List . length g then " \n " else ", " )) g fN [ 1 ] |> Seq . iter ( fun ( n , g )-> printf "%d%s" n g ) fN [ 1 .. 9 ] |> Seq . iter ( fun ( n , g )-> printf "%d%s" n g ) fN [ 1 .. 10 ] |> Seq . iter ( fun ( n , g )-> printf "%d%s" n g ) fN [ 1 .. 11 ] |> Seq . iter ( fun ( n , g )-> printf "%d%s" n g ) 1 1, 2, 3, 4, 5 6, 7, 8, 9 1, 2, 3, 4, 5 6, 7, 8, 9, 10 1, 2, 3, 4, 5 6, 7, 8, 9, 10 11
Factor [edit]
There is no built-in continue in Factor.
1 10 [a,b] [ [ number>string write ] [ 5 mod 0 = "\n" ", " ? write ] bi ] each Fantom [edit]
While and for loops support continue to jump back to begin the next iteration of the loop.
class LoopsContinue { public static Void main () { for (Int i := 1; i <= 10; ++i) { Env.cur.out.print (i) if (i % 5 == 0) { Env.cur.out.printLine ("") continue } Env.cur.out.print (", ") } Env.cur.out.printLine ("") } } Forth [edit]
Although this code solves the task, there is no portable equivalent to "continue" for either DO-LOOPs or BEGIN loops.
: main 11 1 do i dup 1 r. 5 mod 0= if cr else [char] , emit space then loop ; Fortran [edit]
do i = 1 , 10 write ( * , '(I0)' , advance = 'no' ) i if ( mod ( i , 5 ) == 0 ) then write ( * , * ) cycle end if write ( * , '(A)' , advance = 'no' ) ', ' end do C WARNING : This program is not valid ANSI FORTRAN 77 code . It uses C one nonstandard character on the line labelled 500 1. Many F77 C compilers should be okay with it , but it is * not * standard . C C It is also worth noting that FORTRAN 77 uses the command CONTINUE , C but not in the semantic , looping sense of the word . In FORTRAN , C CONTINUE means "do absolutely nothing." It is a placeholder . If C anything , it means "continue to the next line." C C Python does the same thing with ` pass ` ; C and its family of C languages , with `{ /* do nothing */ }` . Write CONTINUE when you need C to write something but have nothing to write . C C This page on Rosetta Code is about a very different "continue" C statement that tells a loop to go back to the beginning . In C FORTRAN , we use ( you guessed it !) a GOTO to accomplish this. PROGRAM CONTINUELOOP INTEGER I DO 10 I = 1 , 10 C Is it five or ten ? IF ( MOD ( I , 5 ) . EQ . 0 ) THEN C If it is , write a newline and no comma . WRITE ( * , 5000 ) I C Continue the loop ; that is , skip to the end of the loop . GOTO 10 ENDIF C Write I with a comma and no newline . WRITE ( * , 5001 ) I C Again , in this case , CONTINUE is completely unrelated to the C semantic , looping sense of the word . 10 CONTINUE STOP C This will print an integer and a newline ( no comma ). 5000 FORMAT ( I3 ) C Standard FORTRAN 77 is completely incapable of completing a C WRITE statement without printing a newline . If you want to print C five integers in standard code , you have to do something like C this : C C FORMAT ( I3 , ',' , I3 , ',' , I3 , ',' , I3 , ',' , I3 ) C C Writing ` 1 , 2 , 3 , 4 , 5 ` and then ` 6 , 7 , 8 , 9 , 10 ` to that format C would produce the following two lines : C C 1 , 2 , 3 , 4 , 5 C 6 , 7 , 8 , 9 , 10 C C However , this code exists to demonstrate continuing a FORTRAN 77 C loop and not to demonstrate how to get around its rigidity about C newlines . C C The dollar sign at the end of the format is a nonstandard C character . It tells the compiler not to print a newline . If you C are actually using FORTRAN 77 , you should figure out what your C particular compiler accepts . If you are actually using Fortran C 90 or later , you should replace this line with the commented C line that follows it . 5001 FORMAT ( I3 , ',' , $ ) C5001 FORMAT ( I3 , ',' , ADVANCE = 'NO' ) END Relying instead upon the looping features of FORMAT [edit]
For historical reasons, 6 is often the default unit number for standard output.
WRITE ( 6 , 1 ) ( I , I = 1 , 10 ) 1 FORMAT ( 4 ( 1 X , I0 , "," ), 1 X , I0 ) END Here the break and continuation comes through the workings of the FORMAT interpreter. The feature 4(etc) means four repetitions of the format items within the brackets, and as each datum from the WRITE statement arrives, it is aligned with the next format item that can receive a datum, the I-format specifier (here I0, which means an integer of only as many digits as are needed for the value) and until such a reciever is encountered, intervening format items are acted upon - 1X means "one space", and the quotes surround a text literal. Accordingly, the first datum generates a space, a one-digit value, and a comma, as does the second and so on. When the sixth datum is received, the end of the format statement has been reached, and the convention is to write the current line and start a new line of output, and further, go back in the FORMAT specification to the first-encountered open-bracket symbol (the rightmost) which in this case is not the beginning of the FORMAT statement but the one that has a repetition count of four in front of it, and, resume interpretation. When the last datum has been accepted, naturally, the line is printed.
An alternative might be FORMAT (4(I2,","),I2) but that would generate
1, 2, 3, 4, 5 6, 7, 8, 9,10
Alternatively, FORMAT (4(I2,","),I2,/,4(I2,","),I3) would do the trick but there would no longer be the loop, break, continue aspect to the interpretation of the FORMAT statement, merely a grinding through a list.
This sort of scheme facilitates a compact way of printing a table with a heading, where the WRITE statement simply pours forth the data and relies on something like FORMAT("heading",/,(complex details for one line)) - thus printing the table line-by-line with only the first line having the heading, a saving on having a write and format statement pair for the heading and a second pair for the table body.
FutureBasic [edit]
include "NSLog.incl" long num for num = 1 to 10 if ( num mod 5 ) NSLog(@"%ld, \b",num) else NSLog(@"%ld",num) end if next HandleEvents Gambas [edit]
Click this link to run this code
Public Sub Main () Dim siCount As Short For siCount = 1 To 10 Print siCount ; If siCount <> 5 And siCount <> 10 Then Print "," ; If siCount = 5 Then Print gb . NewLine ; Next End Output:
1,2,3,4,5 6,7,8,9,10
GAP [edit]
for i in [ 1 .. 11 ] do if RemInt ( i , 5 ) = 0 then Print ( i , "\n" ) ; continue ; fi ; Print ( i , ", " ) ; od ; # 1, 2, 3, 4, 5 # 6, 7, 8, 9, 10 GML [edit]
for(i = 1; i <= 10; i += 1) { show_message(string(i)) i += 1 if(i <= 10) continue } Go [edit]
package main import "fmt" func main () { for i := 1 ; i <= 10 ; i ++ { fmt . Printf ( "%d" , i ) if i % 5 == 0 { fmt . Printf ( "\n" ) continue } fmt . Printf ( ", " ) } } 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Groovy [edit]
for ( i in 1 .. 10 ) { print i if ( i % 5 == 0 ) { println () continue } print ', ' } Haskell [edit]
As a functional language, it is not idiomatic to have true loops - recursion is used instead. Below is one of many possible implementations of the task. The below code uses a guard (| symbol) to compose functions differently for the two alternative output paths, instead of using continue like in an imperative language.
import Control.Monad ( forM ) main = forM [ 1 .. 10 ] out where out x | x ` mod ` 5 == 0 = print x | otherwise = ( putStr . ( ++ ", " ) . show ) x Haxe [edit]
for ( i in 1 ... 11 ) { Sys . print ( i ); if ( i % 5 == 0 ) { Sys . print ( ' \n ' ); continue ; } Sys . print ( ', ' ); } HicEst [edit]
DO i = 1, 10 IF( MOD(i, 5) == 1 ) THEN WRITE(Format="i3") i ELSE WRITE(APPend, Format=" ',', i3 ") i ENDIF ENDDO Icon and Unicon [edit]
The following code demonstrates the use of 'next' (the reserved word for 'continue'):
However, the output sequence can be written without 'next' and far more succinctly as:
Io [edit]
for ( i , 1 , 10 , write ( i ) if ( i % 5 == 0 , writeln () ; continue ) write ( " ," ) ) J [edit]
J is array-oriented, so there is very little need for loops. For example, one could satisfy this task this way:
_2 }." 1 'lq<, >' 8 !: 2 >: i . 2 5 J does support loops for those times they can't be avoided (just like many languages support gotos for those time they can't be avoided).
3 : 0 ] 10 z =. '' for_i . 1 + i . y do. z =. z , ": i if. 0 = 5 | i do. z 1 !: 2 ] 2 z =. '' continue. end. z =. z , ', ' end. i . 0 0 ) Though it's rare to see J code like this.
Java [edit]
for ( int i = 1 ; i <= 10 ; i ++ ){ System . out . print ( i ); if ( i % 5 == 0 ){ System . out . println (); continue ; } System . out . print ( ", " ); } JavaScript [edit]
Using the print() function from Rhino or SpiderMonkey.
var output = "" ; for ( var i = 1 ; i <= 10 ; i ++ ) { output += i ; if ( i % 5 == 0 ) { print ( output ); output = "" ; continue ; } output += ", " ; }
Stepping back from any assumption that repetitive patterns of computation necessarily entail 'loops', and using a functional idiom of JavaScript, we can make the value of one or more subexpressions in a reduce() fold conditional on any special cases that we define.
For example:
function rng ( n ) { return n ? rng ( n - 1 ). concat ( n ) : []; } console . log ( rng ( 10 ). reduce ( function ( a , x ) { return a + x . toString () + ( x % 5 ? ', ' : '\n' ); }, '' ) ); Output:
1 , 2 , 3 , 4 , 5 6 , 7 , 8 , 9 , 10 jq [edit]
jq does not have a "continue" statement. In jq 1.4, the simplest way to accomplish the given task is probably as follows:
reduce range(1;11) as $i (""; . + "\($i)" + (if $i % 5 == 0 then "\n" else ", " end)) Jsish [edit]
/* Loop/continue in jsish */ for ( var i = 1 ; i <= 10 ; i ++ ) { printf ( "%d" , i ); if ( i % 5 == 0 ) { printf ( "\n" ); continue ; } printf ( ", " ); } prompt$ jsish loop-continue.jsi 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Julia [edit]
for i in 1 : 10 print ( i ) if i % 5 == 0 println () continue end print ( ", " ) end 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Kotlin [edit]
// version 1.1.2 fun main ( args : Array < String > ) { for ( i in 1 .. 10 ) { if ( i % 5 == 0 ) { println ( i ) continue } print ( "$i, " ) } } 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Lambdatalk [edit]
{ def loops_continue { lambda { :i } { if { > :i 10 } then ( end of loop ) else { if { = :i 6 } then { br } :i else :i } { if { = :i 10 } then . else , } { loops_continue { + :i 1 }}}}} -> loops_continue { loops_continue 0 } -> 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 . ( end of loop ) langur [edit]
for .i of 10 { write .i if .i div 5 { writeln(); next } write ", " } Lasso [edit]
loop ( 10 ) => {^ loop_count loop_count % 5 ? ', ' | ' \r ' loop_count < 100 ? loop_continue 'Hello, World!' // never gets executed ^} Lingo [edit]
str = "" repeat with i = 1 to 10 put i after str if i mod 5 = 0 then put RETURN after str next repeat end if put ", " after str end repeat put str Lisaac [edit]
1.to 10 do { i : INTEGER; i.print; (i % 5 = 0).if { '\n'.print; } else { ','.print; }; }; LiveCode [edit]
repeat with n = 1 to 10 put n if n is 5 then put return if n < 10 and n is not 5 then put "," end repeat Lua [edit]
for i = 1 , 10 do io.write ( i ) if i % 5 == 0 then io.write ( " \n " ) else io.write ( ", " ) end end or
for i = 1 , 10 do io.write ( i ) if i % 5 == 0 then io.write ( " \n " ) goto continue end io.write ( ", " ) :: continue :: end M2000 Interpreter [edit]
Module Checkit { \\ A For {} loop For i=1 to 10 { Print i; if i mod 5 Else Print : continue Print ","; } Print i=11 \\ A For Next loop For i=1 to 10 Print i; if i mod 5 Else Print : continue Print ","; Next i Print i=11 \\ A for loop using a block and a Loop statement i=0 { i++ if i>10 then Exit loop Print i; if i mod 5 Else Print : continue Print ","; } Print i=11 \\ as above but end value for i=10 not 11 i=0 { i++ if i<10 then loop Print i; if i mod 5 Else Print : continue Print ","; } Print i=10 ' not 11 but 10 } Checkit Maple [edit]
for i from 1 to 10 do printf( "%d", i ); if irem( i, 5 ) = 0 then printf( "\n" ); next end if; printf( ", " ) end do: This can also be done as follows, but without the use of "next".
for i to 10 do printf( "%d%s", i, `if`( irem( i, 5 ) = 0, "\n", ", " ) ) end do: Mathematica/Wolfram Language [edit]
tmp = "" ; For [ i = 1 , i <= 10 , i ++ , tmp = tmp <> ToString [ i ]; If [ Mod [ i , 5 ] == 0 , tmp = tmp <> "\n" ; , tmp = tmp <> ", " ; ]; ]; Print [ tmp ] MATLAB / Octave [edit]
Loops are considered slow in Matlab and Octave, it is preferable to vectorize the code.
or
disp ( reshape ([ 1 : 10 ], 5 , 2 ) ' ) A non-vectorized version of the code is shown below in Octave
for i = 1 : 10 printf ( ' %2d' , i ); if ( mod ( i , 5 ) == 0 ) printf ( '\n' ); continue end end Maxima [edit]
/* There is no "continue" in Maxima, the easiest is using a "if" instead */ block ( [ s : "" ], for n thru 10 do ( s : sconcat ( s , n ), if mod ( n , 5 ) = 0 then ( ldisp ( s ), s : "" ) else ( s : sconcat ( s , ", " ) ) ) )$ MAXScript [edit]
for i in 1 to 10 do ( format "%" i if mod i 5 == 0 then ( format "\n" continue ) continue format ", " ) Insert non-formatted text here
Metafont [edit]
Metafont has no a continue (or similar) keyword. As the Ada solution, we can complete the task just with conditional.
string s; s := ""; for i = 1 step 1 until 10: if i mod 5 = 0: s := s & decimal i & char10; else: s := s & decimal i & ", " fi; endfor message s; end Since message append always a newline at the end, we need to build a string and output it at the end, instead of writing the output step by step.
Note: mod is not a built in; like TeX, "bare Metafont" is rather primitive, and normally a set of basic macros is preloaded to make it more usable; in particular mod is defined as
primarydef x mod y = (x-y*floor(x/y)) enddef; Modula-3 [edit]
Modula-3 defines the keyword RETURN as an exception, but when it is used with no arguments it works just like continue in C.
Note, however, that RETURN only works inside a procedure or a function procedure; use EXIT otherwise.
Module code and imports are omitted.
FOR i := 1 TO 10 DO IO . PutInt ( i ); IF i MOD 5 = 0 THEN IO . Put ( "\n" ); RETURN ; END ; IO . Put ( ", " ); END ; MOO [edit]
s = "" ; for i in [ 1 .. 10 ] s + = tostr (i); if (i % 5 == 0 ) player : tell (s); s = "" ; continue ; endif s + = ", " ; endfor Neko [edit]
/** Loops/Continue in Neko Tectonics: nekoc loops-continue.neko neko loops-continue */ var index = 0 ; while index < 10 { index += 1 ; $print ( index ); if $not ( $istrue ( index % 5 )) { $print ( "\n" ); continue ; } $print ( ", " ); } prompt$ nekoc loops-continue.neko prompt$ neko loops-continue.n 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Nemerle [edit]
using System ; using System . Console ; using Nemerle . Imperative ; module Continue { Main () : void { foreach ( i in [ 1 .. 10 ]) { Write ( i ); when ( i % 5 == 0 ) { WriteLine (); continue ;} Write ( ", " ); } } } NetRexx [edit]
/* NetRexx */ options replace format comments java crossref savelog symbols nobinary say say 'Loops/Continue' nul = '\-' loop i_ = 1 to 10 say i_. right ( 2 ) || nul if i_ // 5 = 0 then do say iterate i_ end say ', ' || nul end i_ NewLISP [edit]
( for ( i 1 10 ) ( print i ) ( if ( = 0 ( % i 5 )) ( println ) ( print ", " ))) Nim [edit]
for i in 1 .. 10 : if i mod 5 == 0 : echo i continue stdout . write i , ", " NS-HUBASIC [edit]
10 FOR I=1 TO 10 20 PRINT I; 30 IF I-I/5*5=0 THEN PRINT :GOTO 50"CONTINUE 40 PRINT ","; 50 NEXT Objeck [edit]
class Continue { function : Main(args : String[]) ~ Nil { for(i := 1; i <= 10; i += 1;) { if(i = 5) { "{$i}, "->PrintLine(); continue; }; "{$i}, "->Print(); }; } } OCaml [edit]
There is no continue statement for for loops in OCaml, but it is possible to achieve the same effect with an exception.
# for i = 1 to 10 do try print_int i ; if ( i mod 5 ) = 0 then raise Exit ; print_string ", " with Exit -> print_newline () done ;; 1 , 2 , 3 , 4 , 5 6 , 7 , 8 , 9 , 10 - : unit = () Though even if the continue statement does not exist, it is possible to add it with camlp4.
Octave [edit]
v = "" ; for i = 1 : 10 v = sprintf ( "%s%d" , v , i ); if ( mod ( i , 5 ) == 0 ) disp ( v ) v = "" ; continue endif v = sprintf ( "%s, " , v ); endfor Oforth [edit]
: loopCont | i | 10 loop: i [ i dup print 5 mod ifZero: [ printcr continue ] "," . ] ; Ol [edit]
We use continuation to break the execution of the inner body.
( let loop (( i 1 )) ( when ( less? i 11 ) ( call/cc ( lambda ( continue ) ( display i ) ( when ( zero? ( mod i 5 )) ( print ) ( continue #f )) ( display ", " ))) ( loop ( + i 1 )))) 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Oz [edit]
By using the "continue" feature of the for-loop, we bind C to a nullary procedure which, when invoked, immediately goes on to the next iteration of the loop.
for I in 1..10 continue:C do {System.print I} if I mod 5 == 0 then {System.printInfo "\n"} {C} end {System.printInfo ", "} end PARI/GP [edit]
for(n=1,10, print1(n); if(n%5 == 0, print();continue); print1(", ") ) Pascal [edit]
See Delphi
Perl [edit]
foreach ( 1 .. 10 ) { print $_ ; if ( $_ % 5 == 0 ) { print "\n" ; next ; } print ', ' ; } It is also possible to use a goto statement to jump over the iterative code section for a particular loop:
foreach ( 1 .. 10 ) { print $_ ; if ( $_ % 5 == 0 ) { print "\n" ; goto MYLABEL ; } print ', ' ; MYLABEL: } Phix [edit]
with javascript_semantics for i = 1 to 10 do printf ( 1 , "%d" , i ) if remainder ( i , 5 )= 0 then printf ( 1 , "\n" ) continue end if printf ( 1 , ", " ) end for
1, 2, 3, 4, 5 6, 7, 8, 9, 10
The following works just as well, with identical output
with javascript_semantics for i = 1 to 10 do printf ( 1 , "%d" , i ) if remainder ( i , 5 )= 0 then printf ( 1 , "\n" ) else printf ( 1 , ", " ) end if end for
PHP [edit]
for ( $i = 1 ; $i <= 10 ; $i ++ ) { echo $i ; if ( $i % 5 == 0 ) { echo " \n " ; continue ; } echo ', ' ; } Picat [edit]
Picat doesn't have a continue statement. So I just use a conditional that ends the body of the predicate.
main => foreach (I in 1..10) printf("%d", I), if (I mod 5 == 0) then nl else printf(", ") end, end. 1, 2, 3, 4, 5 6, 7, 8, 9, 10
PicoLisp [edit]
PicoLisp doesn't have an explicit 'continue' functionality. It can always be emulated with a conditional expression.
(for I 10 (print I) (if (=0 (% I 5)) (prinl) (prin ", ") ) ) Pike [edit]
int main (){ for ( int i = 1 ; i <= 10 ; i ++ ){ write ( sprintf ( "%d" , i )); if ( i % 5 == 0 ){ write ( " \n " ); continue ; } write ( ", " ); } } PL/I [edit]
loop: do i = 1 to 10; put edit (i) (f(3)); if mod(i,5) = 0 then do; put skip; iterate loop; end; put edit (', ') (a); end; Plain English [edit]
In Plain English, continue is spelled repeat and is the only way to specify an end of a loop.
To run: Start up. Demonstrate continue. Wait for the escape key. Shut down. To demonstrate continue: If a counter is past 10, exit. Convert the counter to a string. Write the string on the console without advancing. If the counter is evenly divisible by 5, write "" on the console; repeat. Write ", " on the console without advancing. Repeat. Pop11 [edit]
lvars i; for i from 1 to 10 do printf(i, '%p'); if i rem 5 = 0 then printf('\n'); nextloop; endif; printf(', ') endfor; PowerShell [edit]
for ( $i = 1 ; $i -le 10 ; $i ++) { Write-Host -NoNewline $i if ( $i % 5 -eq 0 ) { Write-Host continue } Write-Host -NoNewline ", " } Prolog [edit]
Prolog doesn't have a continue statement. So I just use a conditional that ends the body of the predicate.
:- initialization ( main ). print_list ( Min , Max ) :- Min < Max , write ( Min ), Min1 is Min + 1 , ( Min mod 5 =:= 0 -> nl ; write ( ',' ) ), print_list ( Min1 , Max ). print_list ( Max , Max ) :- write ( Max ), nl . main :- print_list ( 1 , 10 ). 1,2,3,4,5 6,7,8,9,10
Python [edit]
for i in xrange ( 1 , 11 ): if i % 5 == 0 : print i continue print i , "," , Quackery [edit]
10 times [ i^ 1+ dup echo 5 mod 0 = iff cr done say ", " ] R [edit]
for ( i in 1 : 10 ) { cat ( i ) if ( i %% 5 == 0 ) { cat ( "\n" ) next } cat ( ", " ) } Racket [edit]
It is possible to skip loop iterations in Racket, but an explicit continue construct is rarely used:
#lang racket ;; Idiomatic way ( for ([ i ( in-range 1 11 )]) ( if ( = ( remainder i 5 ) 0 ) ( printf "~a~n" i ) ( printf "~a, " i ))) ;; Forces a skip, but not idiomatic because ;; the logic is less obvious ( for ([ i ( in-range 1 11 )] #:unless ( and ( = ( remainder i 5 ) 0 ) ( printf "~a~n" i ))) ( printf "~a, " i )) Raku [edit]
(formerly Perl 6)
for 1 .. 10 { .print; if $_ %% 5 { print "\n"; next; } print ', '; } or without using a loop:
$_.join(", ").say for [1 .. 5], [6 .. 10]; REBOL [edit]
REBOL [ Title: "Loop/Continue" URL: http://rosettacode.org/wiki/Loop/Continue ] ; REBOL does not provide a 'continue' word for loop constructs, ; however, you may not even miss it: print "One liner (compare to ALGOL 68 solution):" repeat i 10 [ prin rejoin [ i either 0 = mod i 5 [ crlf ][ ", " ]]] print [ crlf "Port of ADA solution:" ] for i 1 10 1 [ prin i either 0 = mod i 5 [ prin newline ][ prin ", " ] ] One liner (compare to ALGOL 68 solution): 1, 2, 3, 4, 5 6, 7, 8, 9, 10 Port of ADA solution: 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Red [edit]
repeat i 10 [ prin i if i = 10 [break] either i = 5 [print ""][prin ","] ] 1,2,3,4,5 6,7,8,9,10 REXX [edit]
version 1 [edit]
(This program could be simpler by using a then/else construct, but an iterate was used to conform to the task.)
/*REXX program illustrates an example of a DO loop with an ITERATE (continue). */ do j= 1 for 10 /*this is equivalent to: DO J=1 TO 10 */ call charout , j /*write the integer to the terminal. */ if j// 5 \== 0 then do /*Not a multiple of five? Then ··· */ call charout , ", " /* write a comma to the terminal, ··· */ iterate /* ··· & then go back for next integer.*/ end say /*force REXX to display on next line. */ end /*j*/ /*stick a fork in it, we're all done. */ Program note: the comma ( , ) immediately after the charout BIF indicates to use the terminal output stream.
output
1, 2, 3, 4, 5 6, 7, 8, 9, 10
version 2 [edit]
/*REXX program illustrates an example of a DO loop with an ITERATE (continue). */ $ = /*nullify the variable used for display*/ do j= 1 for 10 /*this is equivalent to: DO J=1 TO 10 */ $ = $ || j', ' /*append the integer to a placeholder. */ if j// 5 == 0 then say left ( $ , length ( $ ) - 2 ) /*Is J a multiple of five? Then SAY.*/ if j== 5 then $ = /*start the display line over again. */ end /*j*/ /*stick a fork in it, we're all done. */ output is the same as the 1st REXX version.
Ring [edit]
for i = 1 TO 10 see i if i % 5 = 0 see nl loop ok see ", " next Ruby [edit]
for i in 1 .. 10 do print i if i % 5 == 0 then puts next end print ', ' end The "for" look could be written like this:
( 1 .. 10 ) . each do | i | ... 1 . upto ( 10 ) do | i | ... 10 . times do | n | i = n + 1 ; ... Without meeting the criteria (showing loop continuation), this task could be written as:
( 1 .. 10 ) . each_slice ( 5 ){ | ar | puts ar . join ( ", " )} Rust [edit]
fn main () { for i in 1 ..= 10 { print! ( "{}" , i ); if i % 5 == 0 { println! (); continue ; } print! ( ", " ); } } Salmon [edit]
iterate (x; [1...10]) { print(x); if (x % 5 == 0) { print("\n"); continue; }; print(", "); }; Sather [edit]
There's no continue! in Sather. The code solve the task without forcing a new iteration.
class MAIN is main is i:INT; loop i := 1.upto!(10); #OUT + i; if i%5 = 0 then #OUT + "\n"; else #OUT + ", "; end; end; end; end; Scala [edit]
Scala doesn't have a continue keyword. However, you may not even miss it, if could be used here.
The intuitive way [edit]
for ( i <- 1 to 10 ) { print ( i ) if ( i % 5 == 0 ) println () else print ( ", " ) } Functional solution [edit]
Thinking In Scala© says: we avoid for loops and handle it the Functional way:
- Create a Range 1..10 included
- Split the range after converting to a List to a pair of List's
- A List of the elements of pair of will be created: List(List(1,2,3,4,5),List(6,7,8,9,10))
- The map makes for both elements in the List a conversion to a comma separated String, yielding a List of two Strings.
- Both comma separated strings will be separated by an EOL
val a = ( 1 to 10 /*1.*/ ). toList . splitAt ( 5 ) //2. println ( List ( a . _1 , a . _2 ) /*3.*/ . map ( _ . mkString ( ", " ) /*4.*/ ). mkString ( "\n" ) /*5.*/ ) Scheme [edit]
This example is incorrect. It does not accomplish the given task. Please fix the code and remove this message.
( define ( loop i ) ( if ( > i 10 ) 'done ( begin ( display i ) ( cond (( zero? ( modulo i 5 )) ( newline ) ( loop ( + 1 i ))) ( else ( display ", " ) ( loop ( + 1 i ))))))) Scilab [edit]
for i=1:10 printf("%2d ",i) if modulo(i,5)~=0 then printf(", ") continue end printf("\n") end 1 , 2 , 3 , 4 , 5 6 , 7 , 8 , 9 , 10
Sidef [edit]
for i in ( 1 .. 10 ) { print i if ( i % % 5) { print " \n " next } print ', ' } Simula [edit]
! Loops/Continue - simula67 - 07/03/2017; begin integer i; for i:=1 step 1 until 10 do begin outint(i,5); if mod(i,5)=0 then begin outimage; goto loop end; outtext(", "); loop: end end 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Smalltalk [edit]
actually works with all dialects ¹
1 to: 10 do: [ : i | [ : continue | i % 5 = 0 ifTrue: [ Transcript show: i ; cr . continue value ]. Transcript show: i ; show: ', ' . ] valueWithExit . ] ¹ if valueWithExit is not present in the Block class, it can be added as:
valueWithExit ^ self value:[^ nil] Spin [edit]
con _clkmode = xtal1 + pll16x _clkfreq = 80_000_000 obj ser : "FullDuplexSerial.spin" pub main | i ser.start(31, 30, 0, 115200) repeat i from 1 to 10 ser.dec(i) if i // 5 ser.str(string(", ")) next ser.str(string(13,10)) waitcnt(_clkfreq + cnt) ser.stop cogstop(0) 1, 2, 3, 4, 5 6, 7, 8, 9, 10
SPL [edit]
> n, 1..10 s += n ? n%5, s += ", " >> n%5 #.output(s) s = "" < 1, 2, 3, 4, 5 6, 7, 8, 9, 10
SQL PL [edit]
version 9.7 or higher.
With SQL PL:
--#SET TERMINATOR @ SET SERVEROUTPUT ON @ BEGIN DECLARE I SMALLINT DEFAULT 1; Loop: WHILE (I <= 10) DO CALL DBMS_OUTPUT.PUT(I); SET I = I + 1; IF (MOD(I - 1, 5) = 0) THEN CALL DBMS_OUTPUT.PUT_LINE(' '); ITERATE Loop; END IF; CALL DBMS_OUTPUT.PUT(', '); END WHILE Loop; END @ Output:
db2 => BEGIN ... db2 (cont.) => END @ DB20000I The SQL command completed successfully. 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Stata [edit]
See continue in Stata help. Notice that the _continue option of display has another purpose: it suppresses the automatic newline at the end of the display command.
forvalues n=1 / 10 { display `n' _continue if mod(`n',5)== 0 { display continue } display ", " _continue } Suneido [edit]
ob = Object() for (i = 1; i <= 10; ++i) { ob.Add(i) if i is 5 { Print(ob.Join(',')) ob = Object() } } Print(ob.Join(',')) Swift [edit]
for i in 1. .. 10 { print ( i , terminator : "" ) if i % 5 == 0 { print () continue } print ( ", " , terminator : "" ) } 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Tcl [edit]
for {set i 1 } { $i <= 10 } { incr i} { puts -nonewline $i if { $i % 5 == 0 } { puts "" continue } puts -nonewline ", " } Transact-SQL [edit]
DECLARE @i INT = 0; DECLARE @str VarChar(40) = ''; WHILE @i<10 BEGIN SET @i = @i + 1; SET @str = @str + CONVERT(varchar(2),@i); IF @i % 5 = 0 BEGIN PRINT @str; SET @str ='' CONTINUE; END SET @str = @str +', '; END; TUSCRIPT [edit]
$$ MODE TUSCRIPT numbers="" LOOP n=1,10 numbers=APPEND (numbers,", ",n) rest=n%5 IF (rest!=0) CYCLE PRINT numbers numbers="" ENDLOOP 1, 2, 3, 4, 5 6, 7, 8, 9, 10
UNIX Shell [edit]
Z = 1 while (( Z<= 10 )) ; do echo -e " $Z \c" if (( Z % 5 != 0 )) ; then echo -e ", \c" else echo -e "" fi (( Z++ )) done for (( i = 1 ;i<= 10 ;i++)) ; do echo -n $i if [ $((i%5)) -eq 0 ] ; then echo continue fi echo -n ", " done UnixPipes [edit]
yes \ | cat -n | head -n 10 | xargs -n 5 echo | tr ' ' , Ursa [edit]
decl int i for (set i 1) (< i 11) (inc i) if (= (mod i 5) 0) out i endl console continue end if out i ", " console end for Vala [edit]
for ( int i = 1 ; i <= 10 ; i ++ ) { stdout . printf ( "%d" , i ); if ( i % 5 == 0 ) { stdout . printf ( " \n " ); continue ; } stdout . printf ( ", " ); } VBA [edit]
Public Sub LoopContinue () Dim value As Integer For value = 1 To 10 Debug . Print value ; If value Mod 5 = 0 Then 'VBA does not have a continue statement Debug . Print Else Debug . Print "," ; End If Next value End Sub Vedit macro language [edit]
for (#1 = 1; #1 <= 10; #1++) { Num_Type(#1, LEFT+NOCR) if (#1 % 5 == 0) { Type_Newline Continue } Message(", ") } V (Vlang) [edit]
fn main() { for i in 1..11 { print(i) if i%5==0{ println('') continue } print(', ') } } 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Wren [edit]
From v0.4.0 Wren has a continue keyword which works in the expected fashion.
for ( i in 1..10 ) { System . write ( i ) if ( i % 5 == 0 ) { System . print () continue } System . write ( ", " ) } System . print () 1, 2, 3, 4, 5 6, 7, 8, 9, 10
X86 Assembly [edit]
The code got really long, because i manually convert the numbers to ASCII, which gets harder with multiple digits(the number 10). The way you implement continue in X86 Assembly is the same way as how you would create a loop: you just implement a (conditional) jump to another line of code.
extern _printf section .data output db 0 , 0 , 0 , 0 reversedOutput db 0 , 0 section .text global _main _main: mov ecx , 0 looping: inc ecx mov eax , ecx push ecx cmp ecx , 5 je do5 cmp ecx , 10 je do10 don: call createOutput mov [ eax + 1 ], byte 0x2c mov [ eax + 2 ], byte 0x20 push eax call _printf add esp , 4 pop ecx jmp looping do5: call createOutput mov [ eax + 1 ], byte 0x0a push eax call _printf add esp , 4 pop ecx jmp looping do10: call createOutput mov [ eax + 2 ], byte 0x0a push eax call _printf add esp , 4 pop ecx xor eax , eax ret createOutput : ;parameter in eax ;eax between 1 and 99 push ebx mov ecx , 0 clearOutput: mov [ output + ecx ], byte 0 cmp ecx , 3 je next inc ecx jmp clearOutput next: mov ecx , 0 mov ebx , 10 cOlooping: xor edx , edx div ebx mov [ reversedOutput + ecx ], dl add [ reversedOutput + ecx ], byte 0x30 cmp eax , 0 je reverse cmp ecx , 1 je reverse inc ecx jmp cOlooping reverse: mov ecx , -1 mov ebx , 0 name: inc ecx neg ecx mov dl , [ reversedOutput + ecx + 1 ] neg ecx cmp dl , 0 je name mov [ output + ebx ], dl inc ebx cmp ecx , 1 jl name mov eax , output pop ebx ret 1, 2, 3, 4, 5 6, 7, 8, 9, 10
XBasic [edit]
PROGRAM "loopcontinue" DECLARE FUNCTION Entry() FUNCTION Entry () FOR i % = 1 TO 10 PRINT i % ; IF i % MOD 5 = 0 THEN PRINT DO NEXT ' It looks like DO FOR backs to the FOR with the current value of i% END IF PRINT ", " ; NEXT i % END FUNCTION END PROGRAM 1, 2, 3, 4, 5 6, 7, 8, 9, 10
XPL0 [edit]
Like Ada and ALGOL there's no 'continue' command. The task is solved very simply anyway. The commands 'int' and 'rem' are shown spelled out here. Only the first three characters of a command are required.
code CrLf=9, IntOut=11, Text=12; integer N; for N:= 1 to 10 do [IntOut(0, N); if remainder(N/5) \#0\ then Text(0, ", ") else CrLf(0)] 1, 2, 3, 4, 5 6, 7, 8, 9, 10
Yabasic [edit]
for i = 1 to 10 print str$(i); if mod(i, 5) = 0 then print continue end if print ", "; next print end zkl [edit]
foreach n in ([1..10]){print(n); if(n%5==0){println(); continue;} print(", ")} // or foreach n in ([1..10]){print(n,(n%5) and ", " or "\n")} Zig [edit]
const std = @import ( "std" ); pub fn main () ! void { const stdout_wr = std . io . getStdOut (). writer (); var i : i8 = 1 ; while ( i <= 10 ) : ( i += 1 ) { try stdout_wr . print ( "{d}" , .{ i }); if ( i == 5 ) { try stdout_wr . writeAll ( " \n " ); continue ; } try stdout_wr . writeAll ( ", " ); } } Source: https://rosettacode.org/wiki/Loops/Continue
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